0=18b^2-3

Solution for 0=18b^2-3 equation:

0=18b^2-3

We move all terms to the left:

0-(18b^2-3)=0

We add all the numbers together, and all the variables

-(18b^2-3)=0

We get rid of parentheses

-18b^2+3=0

a = -18; b = 0; c = +3;
Δ = b2-4ac
Δ = 02-4·(-18)·3
Δ = 216
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{216}=\sqrt{36*6}=\sqrt{36}*\sqrt{6}=6\sqrt{6}$
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-6\sqrt{6}}{2*-18}=\frac{0-6\sqrt{6}}{-36}
=-\frac{6\sqrt{6}}{-36}
=-\frac{\sqrt{6}}{-6}
$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+6\sqrt{6}}{2*-18}=\frac{0+6\sqrt{6}}{-36}
=\frac{6\sqrt{6}}{-36}
=\frac{\sqrt{6}}{-6}
$